Asked by Hana
A 10-ft,25lb seesaw is balanced by a little girl with a weight of 50lbs and her father with a weight of 200lbs at opposite ends. How far from the seesaw's center of mass must the fulcrum be placed?
Answers
Answered by
Scott
50 (5 + d) + 25 d = 200 (5 - d)
250 + 75 d = 1000 - 200 d
275 d = 750
250 + 75 d = 1000 - 200 d
275 d = 750
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.