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A 10-ft,25lb seesaw is balanced by a little girl with a weight of 50lbs and her father with a weight of 200lbs at opposite ends. How far from the seesaw's center of mass must the fulcrum be placed?

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50 (5 + d) + 25 d = 200 (5 - d)

250 + 75 d = 1000 - 200 d

275 d = 750

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