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A 10% acid solution is to be mixed with a 50% solution to get 200 liters of a 20% solution. How many liters of each solution should be used?

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.1x + .5(200-x) = .2(200)
.1x + 100 -.5x = 40
-.4x + 100 = 40
-.4x + 100-100 = 40-100
-.4x = -60
x = 150
10% at 150 and 50% at 50

Thank you Kuai!

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