A 10.5 g bullet is fired into a 104 g wooden block initially at rest on a horizontal surface.The acceleration of gravity is 9.8 m/s2. After impact, the block slides 6.66 m before coming to rest.If the coefficient of friction between block and surface is 0.658 , what was the speed of the bullet immediately before impact?

Question

A 10.5 g bullet is fired into a 104 g wooden block initially at rest on a horizontal surface.The acceleration of gravity is 9.8 m/s2. After impact, the block slides 6.66 m before coming to rest.If the coefficient of friction between block and surface is 0.658 , what was the speed of the bullet immediately before impact?
Answer in units of m/s.

Scott · Answer

Vbullet = Vblock-bullet * (Mblock-bullet) / Mbullet 1/2 Mbb Vbb^2 = Mbb g * .658 * 6.66 Vbb = √(2 g * .658 * 6.66)