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A 14 g bullet is fired into a 120 g wooden block initially at rest on a horizontal surface. The acceleration of gravity is 9.8 m...Asked by Bri
A 10.5 g bullet is fired into a 104 g wooden block initially at rest on a horizontal surface.The acceleration of gravity is 9.8 m/s2. After impact, the block slides 6.66 m before coming to rest.If the coefficient of friction between block and surface is 0.658 , what was the speed of the bullet immediately before impact?
Answer in units of m/s.
Answer in units of m/s.
Answers
Answered by
Scott
Vbullet = Vblock-bullet * (Mblock-bullet) / Mbullet
1/2 Mbb Vbb^2 = Mbb g * .658 * 6.66
Vbb = √(2 g * .658 * 6.66)
1/2 Mbb Vbb^2 = Mbb g * .658 * 6.66
Vbb = √(2 g * .658 * 6.66)
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