A (10.25) kg bowling ball is hung on a (11.50) m long rope. It is then pulled back until the rope makes an angle of (39.0)o with the vertical and released. Find the tension in the rope when the ball is at the lowest point. Give your answer in N and with 3 significant figures.

Answer 1

The height h thru which it will fall is
H=11.50(1-cos39)

1/2mv^2=mgh
v=sqrt(2gh)

exclamations points are to me a bit exaggerated.