A 10.0kg crate initially at rest on a floor with a static and kinetic coefficient of 0.20 is pushed with a force of 15 N for 4,0 s. the work done is

3 answers

Work is defined as the force applied multiplied by the distance traveled in the direction of the force. In this case, the crate is pushed horizontally, so we need to calculate the distance traveled by the crate.

To find the distance traveled, we can use the equation: distance = (initial velocity)(time) + (1/2)(acceleration)(time^2)

Here, the crate starts at rest, so the initial velocity is 0 m/s. The acceleration can be calculated using the formula: acceleration = force / mass.

Given:
Mass = 10.0 kg
Force = 15 N

Acceleration = Force / Mass
Acceleration = 15 N / 10.0 kg
Acceleration = 1.5 m/s^2

Using the formula for distance:
distance = (0 m/s)(4.0 s) + (1/2)(1.5 m/s^2)(4.0 s)^2
distance = 0 m + (1/2)(1.5 m/s^2)(16 s^2)
distance = (1/2)(1.5 m/s^2)(16 s^2)
distance = (1/2)(1.5 m/s^2)(256 s^2)
distance = (0.75 m/s^2)(256 s^2)
distance = 192 m

Now, we can calculate the work done using the formula: work = force * distance

Work = 15 N * 192 m
Work = 2880 N·m or 2880 Joules

Therefore, the work done on the crate is 2880 Joules.
A 10.0kg crate initially at rest on a floor with a static and kinetic coefficient of 0.20 is pushed with a force of 15 N for 4.0 s. the work done is
The work done on the crate can be calculated using the formula: work = force * distance

To find the distance traveled by the crate, we need to determine if it remains at rest or if it starts to move. If the applied force is greater than or equal to the static friction, the crate will start to move. Otherwise, the crate will continue to remain at rest.

The static friction can be calculated using the equation: static friction = static coefficient * normal force

The normal force acting on the crate is equal to the weight of the crate, which can be calculated using the equation: weight = mass * gravity

Given:
Mass = 10.0 kg
Static coefficient = 0.20
Force = 15 N
Time = 4.0 s

Gravity is approximately 9.8 m/s^2.

Weight = mass * gravity
Weight = 10.0 kg * 9.8 m/s^2
Weight = 98.0 N

Static friction = static coefficient * normal force
Static friction = 0.20 * 98.0 N
Static friction = 19.6 N

Since the applied force (15 N) is less than the static friction (19.6 N), the crate will remain at rest. Therefore, no work is done on the crate.

Thus, the work done on the crate is 0 Joules.