A 10.0-g sample of solid NH4Cl is heated in a 5.00-L container to 900.°C. At equilibrium the pressure of NH3(g) is 1.51 atm.

Question

NH4Cl(s) mc011-1.jpg NH3(g) + HCl(g)
The equilibrium constant, Kp, for the reaction is:

Answer 1

I don't get all of the mumbo jumbo at the end of the question. I assume you want this.
..........NH4Cl --> NH3 + HCl
If pNH3 is 1.51 atm then pHCl is 1.51 atm.
Plug These numbers into the Kp expression and solve.
Kp = pNH3*pHCl
Kp = (1.51)(1.51) = ?
Note that NH4Cl doesn't appear in the Kp expression because it is a solid. Also note that the 10 g and 5.00 L container is just extraneous information. The concentration of NH4Cl, if you want it (but you don't need it) is 1.00.