A 1 L flask is filled with 1.40 g of argon at 25 degrees celcius. A sample of ethane vapor is added to the same flask until the total pressure is 1.00 atm.

Question

Whatis the total pressure of Argon in the flask ?

What is the partial pressure of ethane in the flask?

Answer 1

Use PV = nRT to calculate the pressure of Ar in the flask at the beginning.
Then total pressure = partial pressure Ar + partial pressure ethane.

Answer 2

Please, can you give the answer???

i want to double check

Answer 3

the partial pressure of Argon is .888 atm

Answer 4

1. PV=nRT
Par(1L)=(0.035mol)(0.0821)(25+273)
=0.856 atm

2.Ptotal = Par + Pethane
Pethane= 1.00atm-0.856atm
= 0.144atm

Answer 5

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