A 1-kg rocket is fired straight up from level ground. The engine is able to provide a constant 15N of thrust for exactly 5 seconds after which it shuts of completely. Find the maximum height that the rocket achieves.

Answer 1

WEll, the impulse given is 15*5 Ns=75Ns

Velocity at burnout= 75Ns/1= 75m/s

What was its altditude at this point?

Vf^2=Vi^2+2ad
where a= (F/m -g)

solve for d (height hi)

Now, final height

Vf^2=0=75^2-2g(hf-hi)

solve for hf.

Answer 2

thanks so much...i got 33.3m/s...would u say that's correct?

Answer 3

sorry that was 188 that i got