To find the magnitude of the electric field at either of the other two corners of the square, you can use the formula for the electric field due to a point charge:
Electric field (E) = (k * q) / r^2
Where:
- k is the electrostatic constant (9 x 10^9 Nm^2/C^2)
- q is the charge of the point charge
- r is the distance from the point charge
Step 1: Calculate the distance (r) between the point charge and one of the other corners.
Since the square is 1.00 m on a side, the distance between any two corners is equal to the length of one side of the square. Therefore, r = 1.00 m.
Step 2: Calculate the electric field (E) using the formula.
For the +1.60 nC charge at one corner:
E = (k * q) / r^2
= (9 x 10^9 Nm^2/C^2) * (1.60 x 10^-9 C) / (1.00 m)^2
= 14.4 N/C (rounded to the nearest tenth)
For the -240 nC charge at the diagonally opposite corner, the magnitude of the electric field will be the same since the distance and charge are the same.
Therefore, the magnitude of the electric field at either of the other two corners is 14.4 N/C.
A +1.60 nC point charge is placed at one corner of a square (1.00 m on a side), and a -240 nC charge is placed on the corner diagonally opposite. What is the magnitude of the electric field at either of the other two corners?
in simple steps
1 answer