A 1.50 M solution containing 25 Grams of Al(OH)3 would occupy what volume in liters?

1 answer

1.5 moles/L of solution.

How many moles do we have in 25 g.
25/molar mass Al(OH)3.

M = moles/L
You know M (1.5) and you know moles. Solve for L.