A 1.50 kg sample of a metal sample absorbs 43.5 kJ of heat, resulting in a

Question

Temperature rise of 65.0 °C. What is the specific heat capacity of the metal?

M=1.50kG
Q=43.5kJ
dT=65C

Answer 1

q= mass x specific heat x delta T.
I don't know what units you want sp.h. in but I would convert kJ to J and kg to g. That way sp.h. comes out in J/g*C and you can convert to whatever you want.

Answer 2

Thanks bob that was my problem