d. d = Xo*T = 25m/s * 3s. = 75 m.
e. Tr = 3s/2 = 1.50 s. = Rise time.
e. Y = Yo + g*Tr = 0.
Yo - 9.8*1.5 = 0.
Yo = 14.7 m/s = Ver. component of initial velocity.
f. Tan A = Yo/Xo = 14.7/25 = 0.58800.
A = 30.5o.
A 1.5 tall student throws a baseball with a horizontal component of velocity of 25m/s. It takes 3.00s to come back to its original height.
d. how far did the ball travel horizontally?
e. What is the initial velocity in the y-direction?
f.At what angle is the baseball thrown?
1 answer