Asked by JOHN

A 1.47 x 10^6 kg steel hull has a base that is 2.5 x 10^3 m^2 in area. If it is placed in sea water (density= 1025 kg/m^3), how deep does the hull sink?
Answered by Steve
if the hull sinks x meters, it displaces 2500x m^3 of water.

1m^3 of water weighs 1000kg so

2500*x*1025 = 1.47*10^6
x = 0.573m
Answered by JOHN
Thanx!!!!
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