Ke at A = (1/2)(1.45)(3.25)^2 = 7.66 Joules
Ke at B = (1/2)(1.45)(1.34)^2 = 1.30 Joules
so work done= delta ke = 1.3-7.66 = -6.36 J
B) Now you should be able to continue.
slows during B, speeds up during C
A 1.45 kg book is sliding along a rough horizontal surface. At point A it is moving at 3.25 m/s , and at point B it has slowed to 1.34 m/s .
Part A
How much work was done on the book between A and B?
Part B
If -0.750 J of work is done on the book from B to C, how fast is it moving at point C?
Part C
How fast would it be moving at C if 0.750 J of work were done on it from B to C?
1 answer