A 1.435g of Naphthalene (C10H8) was burned in Constant Volume Bomb Calorimeter. Consequently, temperature of the water rose from 20.17 degrees cerisious to 25.84 degrees cerisious. If the mass of water surrounded the Calorimeter was exactly 2.0×10^3 Kg and the heat capacity of the Bob Calorimeter was was 1.80 Kj/degree cerisious, calculate the molar heat of reaction (combustion) in KJ of Naphthalene.

Question

A 1.435g of Naphthalene (C10H8) was burned in Constant Volume Bomb Calorimeter. Consequently, temperature of the water rose from 20.17 degrees cerisious  to 25.84 degrees cerisious.  If the mass of water surrounded the Calorimeter was exactly 2.0×10^3 Kg and the heat capacity of the Bob Calorimeter was was 1.80 Kj/degree cerisious, calculate the molar heat of reaction (combustion) in KJ of Naphthalene.

DrBob222 · Answer

I have no idea what a degree "cerisious" is but at least you're consistent. I assume you meant "Celsius".
q = mcdT + Ccal*dT
q = 2,000,000 x 4.184 J/C*K x (25.84-20.17) + 1800 J/C x (25.84-20.17).
That gives you q for 1.435 g naphthalene. Convert that to q for the molar mass of naphthalene in grams.
Post your work if you get stuck.

Fillipus · Answer

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