A 1.31-kg block slides across a rough surface such that it slows down with an acceleration of 1.39 m/s2. What is the coefficient of kinetic friction between the block and the surface?

Answer 1

I think you solve it like this...do you have the answer to verify? I am no genius in physics...

Forces in the x direction = friction = mass x acceleration.

friction forces is found by multiplying the coefficient of friction (u) by the normal force.

so. -u x mass x gravity = mass x -acceleration

mass cancels so u = 1.39 / 9.8.

Answer 2

atta go Brenda !