A 1.2-kilogram basketball travelling at 7.5 meters per second hits the back of a 12-kilogram wagon and bounces off a 3.8 meters per second, sending wagon off in the original direction of travel of the ball. How fast is the wagon going?

Answer 1

M1*V1 + M2*V2 = M1*V3 + M2*V4.
1.2*7.5 + 12*0 = 1.2*(-3.8) + 12*V4.
9 + 0 = -4.56 + 12V4.
12V4 = 13.56.
V4 = 1.13 m/s. = Velocity of the wagon.

Answer 2

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