y = 0.051 sin (2 pi *1.2 t ) = 0.051 sin (7.74 t )
dy/dt = velocity = (0.051 * 7.74) cos (7.74 t)
all kinetic energy when cos wt = 1, no potential E then because spring is not stretched (sin w t = 0)
Ke max = (1/2) m vmax^2 = (1/3)(1.2) ( 0.051*7.74)^2 Joules
A 1.2 kg mass attached to a spring oscillates with an amplitude of 5.1 cm
and a frequency of 1.2 Hz. What is its energy of motion?
1 answer