Please proof read. I have no idea what the mass is and am guessing you mean g = about 9.81/6 = 1.64
positive x up
F up = m a =T - m g
so a up =T/m - g
v = Vi + a t
Vi = - 18
at surface v = 0
0 = -18 + a t
a t = 18
h = Hi + Vi t + (1/2) a t^2
0 = 165 - 18 t +(1/2) (18/t) t^2
9 t - 18 t + 165 = 0
9 t = 165
t = 18.3 seconds to stop
a = 18/t = 0.984 m/s^2
now back to
a =T/m - g
0.984 = (T/ whatever mass is) - whatever g is
A 1.14 X 10"-kg lunar landing craft is about to touch down on the surface of the moon, where the acceleration due to gravity is t.60 rn/s1
-
At an altitude of 165 m, the craft's downward velocity is 18.0 rn/s. To
slow d~wn the craft, a retrorocket is firing to provide an upward thrust,
Assuming the descent is vertical, find the magnitude of the thrUst needed
to reduce the velocity to zero at the instant when the craft touches the
lunar surface.
1 answer
1 answer