Asked by Tiangaydonzo
A 1.00Lgas sample at 1.00degree celsius and 600torr contain 50.0%helium and 50.0%xenon by mass. What are the partial pressure of the individual gasses?
Answers
Answered by
DrBob222
Assume any gram size you wish; i.e., say 5g He and 5g Xe (that is 50% by mass).
Then n He = grams/atomic mass = ?
n Xe = grams/atomic mass = ?
total mols = ?
XHe = nHe/total mols and
XXe = nXe/total mols.
Use PV = nRT and solve for total P of the system usig total mols.
Then pHe = XHe*Ptotal
and pXe = XXe*Ptotal
Then n He = grams/atomic mass = ?
n Xe = grams/atomic mass = ?
total mols = ?
XHe = nHe/total mols and
XXe = nXe/total mols.
Use PV = nRT and solve for total P of the system usig total mols.
Then pHe = XHe*Ptotal
and pXe = XXe*Ptotal
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