Use PV = nRT.
n = 1.00g/molar mass H2O
Don't forget T must be in kelvin.
a 1.00g sample of water is allowed to vaporize completely in a 10.0L container. What is the pressure of the water vapor at 150 degrees celsius?
2 answers
PV=nRT
P=?
V=10L
n=0.056mol
R=0.082 atm*l/mol*K
T=423K
P=nRT/V
P=(0.056mol)(0.082atm*l/mol*K)(423K)/(10L)
P=0.1942 atm
P=?
V=10L
n=0.056mol
R=0.082 atm*l/mol*K
T=423K
P=nRT/V
P=(0.056mol)(0.082atm*l/mol*K)(423K)/(10L)
P=0.1942 atm
2 answers