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A 1.0 kg rock is thrown straight upward with an initial speed of 8.0 m/s. What is its speed when it reaches a height of 1.6 m?

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1/2 m v1^2 = m g h + 1/2 m v2^2

v1^2 - 2 g h = v2^2

8.0^2 - (2 * 9.8 * 1.6) = v2^2

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