A .055 gram sample of aluminum hydroxide is reacted with .200M hydrochloric acid. How many mL of the acid are needed to neutralize the aluminum hydroxide?

Answer 1

1. Write and balance the equation.
2. Convert 0.055 g Al(OH)3 to moles. moles = grams/molar mass.
3. Using the coefficients in the balanced equation, convert moles Al to moles HCl.
4. Molarity = moles HCl/L of HCl.
You know moles HCl and Molarity; calculate L of HCl.