Assume mechanical (potential + kinetic) energy is conserved after the block is released.
(1/2) k x^2 = M g (0.545 sin45)
Solve for the spring compression x.
There needs to be a smooth transition where the ramp changes from horizontal to 45 degrees up. Otherwise, some emergy will be lost there.
A 0.8 kg block is shot horizontally from a spring, as in the example above, and travels 0.545 m up a long a frictionless ramp before coming to rest and sliding back down. If the ramp makes an angle of 45.0° with respect to the horizontal, and the spring originally was compressed by 0.17 m, find the spring constant.
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