A 0.7 kg object is at rest. A 6.5 N force to the right acts on the object during a time interval of 3.7 seconds. What is the velocity of the object at the end of this interval?

1 answer

F = ma
6.5 = .7a
a = 6.5/.7

v = at = 6.5/.7 * 3.7 = 34.357