A 0.600-kg aluminum teakettle contains 4.00 kg of water at 26.0° C. How much heat is required to raise the temperature of the water (and kettle) to 100.0° C?

Answer 1

Q = c(Al)•m(Al)•Δt + c(wat)•m(wat)• Δt =
=(930•0.6 +4180•4) •74 =1,278,572 J= =1.2•10^6 J = 1.2 MJ