A 0.60 kg object with an initial velocity of 3.0 m/s in the positive x direction is acted on by a force in the direction of motion. The force does +2.5 J of work. What is the final velocity of the object?

Question

Henry · Answer

KE = KE1 + KE2 = 0.5*M*V^2 + KE2 = 0.5*0.6*3^2 + 2.5 = 5.2 J. KE = 0.5*0.6*V^2 = 5.2 V^2 = 17.33 V = 4.16 m/s.

Anonymous · Answer

A 0.60 kg Volleyball is moving with a intial velocity of 8 m/s and final velocity of 16 m/s. What is the total work done of this object? *