A 0.6-kg object moves in a horizontal circular track with a radius of 3.3m. An external force of 6.8 N, always tangent to the track , causes the object to speed up as it goes around. The work done by the external force as the object makes one revolution is equal to what value in Joule?
1 answer
force * distance in direction of the force = work done by force = 6.8 N * 2 pi * 3.3 meters = 141 Joules
1 answer