figure the percent iron in Fe2O3..
percent= 2*atomicmassFe/formulamassFe2O3
then, percent in the sample
= percentabove*.3210/.5962
A 0.5962g sample of iron ore is dissloved in acid producing Fe3+. Though a series of reactions, the iron precipitates as the Fe(OH)3. The precipitates is heated, forming solid Fe2O3. What is the mass % of iron in the sample if the analysis produced 0.3210g Fe2O3?
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