I suppose your original direction was x.
The x momentum will not change since there was no force in the x direction.
x momentum = .55 * 4 = 2.2 kg m/s
I assume z is the horizontal axis perpendicular to x.
tsn 23 = Vz/4
so
Vz = 1.7 m/s
z momentum = .55*1.7 = .934 kg m/s
magnitude of momentum
= sqrt(2.2^2+.934^2)
= 2.39 kg m/s
F * time = impulse = change of momentum
F = 2.39/.0025 = 956 Newtons
A 0.55 kg block of ice is sliding by you on a very slippery floor at 4 m/s. As it goes by, you give it a kick perpendicular to its path. Your foot is in contact with the ice block for 0.0025 seconds. The block eventually slides at an angle of 23 degrees from its original direction (labeled
θ
in the diagram). The overhead view shown in the diagram is approximately to scale. The arrow represents the average force your toe applies briefly to the block of ice.
I found the unit vector to be <0.9205,0,-0.3907>
What is the x-component of the block's momentum after the kick?
What is the magnitude of the block's momentum after the kick?
Use your answers to the preceding questions to find the z-component of the block's momentum after the kick (drawing a diagram is helpful):
What was the magnitude of the average force you applied to the block?
2 answers
Tank u :3