a) ME= 1/2 k x^2
b) 1/2 m v^2=change in PE= 1/2 k (.27^2-.09^2)
A 0.53-kg mass is attached to a horizontal spring with k = 106 N/m. The mass slides across a frictionless surface. The spring is stretched 27 cm from equilibrium, and then the mass is released from rest.
(a) Find the mechanical energy of the system.
(b) Find the speed of the mass when it has moved 9 cm.
(c) Find the maximum speed of the mass.
3 answers
In turns out that for b), instead of using
(.27^2 -0.09^2), we have to use (.27^2-0.18^2).
(.27^2 -0.09^2), we have to use (.27^2-0.18^2).
I think your solution tells us when the spring moves 18 cm, not 9 cm.
Thank you, though. This was really useful.
Thank you, though. This was really useful.
1 answer