M H2S2 initially = 0.0125/0.5 = 0.025M
............2H2S ==> 2H2 + S2
I...........0.025.....0.....0
C............-2x......2x.....x
E.........0.025-2x....2x.....x
Substitute the E line into the Kc expression and solve for x.
A 0.500L vessel initially contains 0.0125 mol of H2S2 . Find the equilibrium concentrations of H2 and S2. Kc = 1.67 x 10^-7
2 H2S <--> 2 H2 + S2
2 answers
I got this equation but now I am lost
1.67x10^-7 = ((4x^2)(x)) / (0.000625-4x^2)
1.67x10^-7 = ((4x^2)(x)) / (0.000625-4x^2)