A 0.500 kg wheel that has a moment of inertia of 0.015 kg m^2 is initially turning at 30 rev/s. it starts to rest after 163 revolution. how large is the torque that slowed it?

Answer 1

wf=wi+2(angular acceleration)*angle
0=(30^2PI)^2+ 2*alpha*163*2PI

solve for alpha, angular acceleration.

Then
Torque=alpha*momentinertia
solve for torque