a. To find the velocity of the object at the end of the 1.50 s interval, we first need to calculate the acceleration the object experienced due to the 3.00 N force acting to the right.
First, calculate the acceleration using Newton's Second Law:
F = ma
3.00 N = (0.50 kg)a
a = 6.00 m/s^2
Now, use the following equation to find the final velocity of the object:
v = u + at
where:
v = final velocity
u = initial velocity (0 m/s as the object is at rest)
a = acceleration (6.00 m/s^2)
t = time interval (1.50 s)
v = 0 + 6.00 m/s^2 * 1.50 s
v = 9.00 m/s
Therefore, the velocity of the object at the end of the 1.50 s interval is 9.00 m/s to the right.
b. Next, to find the velocity at the end of the 3.00 s interval after the 4.00 N force is applied to the left, we first need to calculate the acceleration due to this force.
First, calculate the acceleration using Newton's Second Law:
F = ma
4.00 N = (0.50 kg)a
a = -8.00 m/s^2 (negative sign indicates that the acceleration is to the left)
Now, use the same equation as in part a to find the final velocity at the end of the 3.00 s interval:
v = u + at
where:
v = final velocity
u = 9.00 m/s (velocity at the end of the 1.50 s interval)
a = acceleration (-8.00 m/s^2)
t = time interval (3.00 s)
v = 9.00 m/s + (-8.00 m/s^2) * 3.00 s
v = 9.00 m/s - 24.00 m/s
v = -15.00 m/s
Therefore, the velocity of the object at the end of the 3.00 s interval is 15.00 m/s to the left.
A 0.50 kg object is at rest. A 3.00 N force to the right acts on the object during a time interval of 1.50 s.
a. What is the velocity of the object at the end of this interval?
b. At the end of this interval, a constant force of 4.00 N to the left is applied for 3.00 s. What is the velocity at the end of the 3.00 s?
1 answer
1 answer