A 0.5-L saturated solution of silver chloride, AgCl, is evaporated to dryness. The residue is equivalent to 1.4 x 10^-3 mole. Calculate the experimental value of the Ksp of silver chloride. Show all of your work.

Answer 1

....AgCl ==> Ag^+ + Cl^-
......x.......x......x
mols AgCl = 1.4E-3 mols in 1/2 L; therefore, you will have 1.4E-3 mol x 2 = 2.8E-3 mols in a L.
Ksp = (Ag^+)(Cl^-)
Ag^+ = Cl^- = 2.8E-6
Substitute and solve for Ksp. Not good experimental result.