First determine the molarity of the HCl from the standardization part of the problem (the second part of the problem) using 0.1876 g NaHCO3 and 37.86 mL HCl.
NaHCO3 + HCl ==> NaCl + H2O + CO2
mols NaHCO3 = grams/molar mass
mols HCl = mols NaHCO3
M HCl = mols HCl/L HCl.
Then determine percent NaHCO3 in the unknown which is the first part.
mols HCl = M x L = ?M HCl from above x 0.04072L = ?
mols NaHCO3 = mols HCl
g NaHCO3 = mols x molar mass
%NaHCO3 = (grams NaHCO3/0.4674)*100 = ?
A 0.4671g sample containing sodium bicarbonate was titrated with HCL requiring 40.72ml. The acid was standardized by titrating 0.1876g of sodium carbonate FW 106mg/mmol requiring 37.86ml of the acid. Find the percentage of NAHO3 FW 84mg/mmol in the sample
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3 answers
How many grams of NaCl would be formed from 100 grams of Na2CO3 in the following reaction?
Na2CO3 + 2HCl→2 NaCl+CO2+H2O
Na2CO3 + 2HCl→2 NaCl+CO2+H2O
A.0.4671 gram of sample containing sodium
bicarbonate was dissolved and titrated with a solution
of HCL required 40ml. Calculate the percent sodium
bicarbonate in the sample؟
bicarbonate was dissolved and titrated with a solution
of HCL required 40ml. Calculate the percent sodium
bicarbonate in the sample؟
1 answer