A 0.46 kg mass oscillates in simple harmonic motion on a spring that has a spring constant of 2080 N/m. The spring was initially compressed 9.4 cm (a negative displacement) at t = 0 s. What's the velocity in m/s of the mass at t = 0.24 s?

Answer 1

9.4 cm = 0.094 m
x = -0.094*cos(w*t)
v = dx/dt = 0.094*sin(w*t)

where w = (k/m)^0.5

x is the x position; v is the speed; w is the angular velocity; k is the spring constant; m is the mass

at t = 0.24 s,

v = 0.094*sin(((2080/0.46)^0.5)*0.24)

Answer 2

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