HZ + KOH ==> KZ + H2O
mols KOH = M x L = ?
mols HZ = mols KOH
mols = g/molar mass. You know mols and grams, solve for molar mass.
A 0.456 gram sample of an unknown mono-
protic acid (let’s call it HZ) was dissolved in
some water (you pick the amount). Then the
acidic solution was titrated to the equivalence
point with 32.5 mL of 0.174 M KOH. What
is the molecular weight of the unknown acid
HZ?
1. 103.2 g/mol
2. 187.9 g/mol
3. 80.6 g/mol
4. 85.7 g/mol
5. 0.00259 g/mol
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