A 0.411 mol sample of PCl5(g) is injected into an empty 4.65 L reaction vessel held at 250 °C. Calculate the concentrations of PCl5(g) and PCl3(g) at equilibrium.kc=1.80 at 250c

Answer 1

0.411mols/4.65L = 0.0884M

........PCl5 ==> PCl3 + Cl2
I......0.0884.....0......0
C.......-x........x......x
E.....0.0884-x....x......x

Substitute the E line into K expression and solve for x and 0.0884-x