a. F = 160N/m * 0.15m = 22.5 N.
b. a = F/m = 22.5/0.40 = 56.25 m/s^2.
A 0.40kg object is attached to a spring constant 160N/m so that the object is allowed to move on a horizontal frictionless surface. The object is released from rest when the sprin g is compressed 0.15m find:
a) the force on the object and
b) its acceleration at this instant.
3 answers
F = 160N/m * 0.15m = 24.0 N.
a = F/m = 24.0/0.40 = 60.0 m/s^2.
a = F/m = 24.0/0.40 = 60.0 m/s^2.
A 0.40-kg object is attached to a spring with force constant 160 N/m so that the object is allowed to move on a horizontal frictionless surface. The object is released from rest when the spring is compressed 0.15 m. Find a) the force on the object (b) its acceleration at that instant
2 answers