initial momentum east =.4*5.38
the final momentum east is the same
so
.4 * 5.38 = .4 u + .95 v
where u and v are the two resulting speeds
also kinetic energy is the same
(1/2)(.4)(5.38)^2 = (1/2)(.4)(u)^2 + (1/2)(.95)(v)^2
use those two equations to solve for u and v
A 0.400-kg ice puck, moving east with a speed of 5.38 m/s , has a head-on collision with a 0.950-kg puck initially at rest. Assume that the collision is perfectly elastic.
What is the speed of the 0.400-kg puck after the collision?
1 answer
1 answer