A 0.340 kg particle moves in an xy plane according to x(t) = -15.00 + 2.00t - 4.00t3 and yet) = 25.00 + 7.00t - 9.00t2, with x and y in meters and t in seconds. At t = 0.700 s, what are (a) the magnitude and

Question

A 0.340 kg particle moves in an xy plane according to x(t) = -15.00 + 2.00t - 4.00t3 and yet) = 25.00 + 7.00t - 9.00t2, with x and y in meters and t in seconds. At t = 0.700 s, what are (a) the magnitude and 
(b) the angle (relative to the positive direction of the x axis) of the net force on the particle, and 
(c) what is the anngle of the particle's direction of travel?

i know how to find the answer to the first part.. but since i havent studied applied physics before i need help with the other two... thanks in advance

Bot · Answer

a) The magnitude of the net force on the particle is 8.8 N.

b) The angle of the net force on the particle is -45.3° relative to the positive direction of the x axis.

c) The angle of the particle's direction of travel is -45.3°.