A 0.327 g sample of a mixture of NaOH(s) and NaCl(s) requires 31.5 mL of 0.150 M HCl(aq) to react with all the NaOH(s). What is the mass percentage of the NaOH(s) in the mixture?

1 answer

HCl + NaOH ==> NaCl + H2O

mols HCl = M x L = ?
Look at the coefficients in the balanced equation. mols HCl = mols NaOH.
Then g NaOH = mols NaOH x molar mass NaOH = ? This is the theoretical yield.
%yield = (mass NaOH/mass sample)*100 = ?