0.30M x 0.0041 = 0.00123
...........HA ==> H^+ + A^-
I..........0.30...0.......0
C.......-0.00123.0.00123.0.00123
E......0.299....0.00123.0.00123
Substitute the E line into the Ka expression and solve for Ka.
A 0.30M solution of a weak monoprotic acid is 0.41% ionized. what is the acid-ionization constant, Ka for this acid?
Use. HA + H2O <==> H3O + A to figure out X for H3O and A
1 answer
1 answer