A 0.2800 g sample of an unknown acid requires 28.22 mL of 0.1199 M NaOH for neutralization to a phenolphthalein point.
a.) How many moles of OH- are used?
b.) How many moles of H+ are found in the acid?
c.) What is the calculated equivalent molar mass of the unknown acid?
If I'm doing this right, I got .003384 mol OH- for question a. Here's my work:
28.22 mL NaOH x (1 L/1000 mL) x (.1199 mol NaOH/1 L NaOH) x (1 mol OH-/1 mol Na+)= .003384 mol OH-
However, assuming that is even right, I have no idea where to start on the second two questions. Any guidance would be greatly appreciated. Thank you!
2 answers
Sorry for the double post. Just saw that my original question actually posted though I was told it had not.
Does that mean you saw my response? Do you have additional question on this problem?
1 answer