A 0.25 kg ball moving at 19.0 m/s is hit by a bat. The ball leaves the bat at a speed of 38 m/s in the opposite direction. If the bat is in contact with the ball for 0.01 s, find the magnitude of the average force exerted on the ball by the bat.

Answer 1

force = change in momentum/ time
change in momentum = .25 (38 - -19) = .25 (57)
F = .25 (57) / 0.01 Newtons

Answer 2

V = Vo + a*t =-38.
19 + a*0.01 = -38.
a = ? It will be negative.

F = M*a.