Jake, Spencer, Cab, or whomever. This is worked the same way. Sodium chlorobenzoate is a salt which ionizes in water to produce the chlorobenzoate ion. In water, that gives
ClB _ HOH ==> HClB + OH^-
Set up like the ethylamine problem except Kb for the chlorobenzoate ion = Kw/Ka.
A 0.23 M sodium chlorobenzoate (NaC7H4ClO2) solution has a pH of 8.68. Calculate the pH of a 0.23 M chlorobenzoic acid (HC7H4ClO2) solution
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