A 0.20 kg baseball is pitched horizontally with a speed of + 40 m/s. When it hits the bat a force of 1.7x10^4 N acts on the ball to send it soaring in the opposite direction. If the bat and ball are in contact for 8.0x10^-3 s, what is the impulse delivered to the ball by the bat?

Answer 1

Force * time = change of momentum = impulse
1.4*10^7 * 8 * 10^-3 = impulse

Is there no part b where they ask you the resulting speed ?