A 0.20-kg ball on a stick is whirled on a vertical circle at a constant speed. When the ball is at the three o'clock position, the stick tension is 16 N. Find the tensions in the stick when the ball is at the twelve o'clock and at the six o'clock positions.
mg = 2.4525N
12 O'clock: 16N - 2.4525N = 13.57475N
6 O'clock: 16N + 2.4525N = 18.4525N
Am I correct in this case?
3 answers
Wait I'm off on the answers. But do I basically have the right idea?
yes, but you should only go two sig figures...
at 3 the tension = m v^2/R = .2 v^2/R = 16
so
v^2/R = 80
at the top:
T = 16 - m g = 16 -.2*9.81 = 14 = 16 - 1.96
Note : 1.96 is not 2.45
at the bottom
T = 16 + m g = 17.9
so
v^2/R = 80
at the top:
T = 16 - m g = 16 -.2*9.81 = 14 = 16 - 1.96
Note : 1.96 is not 2.45
at the bottom
T = 16 + m g = 17.9
0 answers