To find the force with which the ball hits the catcher's mitt, we can use Newton's second law of motion, which states that \( F = ma \), where \( F \) is the force, \( m \) is the mass, and \( a \) is the acceleration.
Given:
- Mass of the softball \( m = 0.2 \) kg
- Acceleration of the softball \( a = 8 \) m/s²
Now, we'll calculate the force:
\[ F = ma = (0.2 , \text{kg}) \times (8 , \text{m/s}^2) = 1.6 , \text{N} \]
Thus, the force with which the ball will hit the catcher’s mitt is 1.6 N.
The correct response is 1.6 N.